Question about Poisseuille's law and blood flow

  • Context: Undergrad 
  • Thread starter Thread starter don_anon25
  • Start date Start date
  • Tags Tags
    Blood Flow Law
Click For Summary
SUMMARY

The discussion centers on the application of Poiseuille's law to blood flow in the coronary artery. The formula for flow rate is established as Q = π*(P1-P2)*R^4/(8nL). The viscosity of blood is determined to be approximately three times that of water, resulting in a dynamic viscosity of μ_blood = 62.76 lb_f sec/ft² or 3.0 x 10^6 cP. The length (L) of the coronary artery is not definitively provided, with suggestions to either leave it blank for flow per unit length or to estimate its value.

PREREQUISITES
  • Understanding of Poiseuille's law and its application in fluid dynamics
  • Knowledge of blood viscosity and its comparison to water
  • Familiarity with the anatomy of the coronary artery
  • Basic mathematical skills for fluid flow calculations
NEXT STEPS
  • Research the specific length of the coronary artery in millimeters
  • Learn about the factors affecting blood viscosity in different conditions
  • Explore advanced applications of Poiseuille's law in medical scenarios
  • Investigate the impact of arterial radius on blood flow rates
USEFUL FOR

Medical students, cardiovascular researchers, and professionals in biomedical engineering focusing on fluid dynamics in biological systems.

don_anon25
Messages
35
Reaction score
0
I know that rate of flow is equal to pi*(P1-P2)*R^4/8nL. For blood in the coronary artery, I know the pressure drop, and the radius of the artery. What is the viscosity of blood? I can't find this value anywhere! And what value should I enter for L (distance L along a tube)? Is there an actual value somewhere for the length of the coronary artery in mm?
 
Physics news on Phys.org
According to this source http://www.usc.edu/dept/biomed/bme403/Section_3/viscosity_of_blood.html
The value is approximately three times that of water. So if I use the dynamic viscosity of water at 20°C as
\mu_{water} = 20.92 \frac{Lb_f sec}{ft^2}, that would mean that \mu_{blood} = 3.0 \mu_{water} so...

\mu_{blood}= 62.76 \frac{Lb_f sec}{ft^2}

\mu_{blood}= 3.0 x 10^6 cP

I can't really help you in terms of L in your equation. A couple of options would be to a)Leave L blank and express your answers in flow per unit length (which sounds kind of funny but is technically correct). or b)Make an estimation.
 
Last edited by a moderator:

Similar threads

  • · Replies 2 ·
Replies
2
Views
3K
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
1
Views
6K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
2
Views
2K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
7K
  • · Replies 4 ·
Replies
4
Views
571
  • · Replies 4 ·
Replies
4
Views
2K