- #1

farbror

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I'm trying to prove if X~Po(m) => 2X~Po(2m)

But I'm not sure how to prove or disprove it.

I'm thinking about using the addition formula, but is this the right approach?

X_1~Po(m)

X_2~Po(n)

X_1+X_2~Po(m+n)

n=m => X_1=X_2 => 2X_1~Po(2m)

Any help is appreciate.

Thanks

/farbror