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## Homework Statement

Hello, this is the solution to a problem that i am doing and the only thing i am confused about is why the

C1 in the third step is = to − 1/2 ln 2 √3 as stated in the last line.

=√3/2 sec θ − 1/2 ln |sec θ + tanθ| + C1

that is all i am confused about but i get the rest.

i appreciate the Help Thank you very much.