Hello, this is the solution to a problem that i am doing and the only thing i am confused about is why the
C1 in the third step is = to − 1/2 ln 2 √3 as stated in the last line.
=√3/2 sec θ − 1/2 ln |sec θ + tanθ| + C1
that is all i am confused about but i get the rest.
i appreciate the Help Thank you very much.