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Question about spectroscopic notation

  1. May 30, 2005 #1
    Greetings,

    I'm a bit confused about the notation for multi-electron orbitals.
    For example, you have the notation

    [tex]^{1}D_{2}[/tex],

    which mean a singlet with S=0 L=2, J=2, right?

    Now I've come across the notation (in Slater)

    [tex]^{1}D_{2}^{0}[/tex]

    What's the deal with the extra superscript 0?
     
  2. jcsd
  3. May 30, 2005 #2

    Gokul43201

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    The std. notation, as I'm sure you know is 2S+1XJ, where X = S,P,D,F.

    I've also come across notation that appends nlx in front of the std. notation. Where this extra addition is simply the configuration of the outermost subshell.

    I have no idea what notation Slater is using. But keep in mind that he is a physicist (and hence loathes spectroscopists despite feeding off their data :wink:) and nearly all his books were written in the 60s (or thereabouts).
     
  4. May 30, 2005 #3

    Gokul43201

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    This is correct. Until better info comes along, you can feel safe ignoring the 0.
     
  5. Mar 29, 2010 #4
    The superscript o after the subshell indicates odd parity. When the parity is even, there is no superscript. I hesitate to venture further, because it's a little fuzzy to me as well. I think that the odd parity results if you get a negative value when summing spins, like if you have a total negative spin. This thread is so old, I don't know if anybody even cares.
     
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