- #1
billy722
- 19
- 0
Homework Statement
i can not find the N.
what i can only found is:
D0=0.02mm;V=0.25;E=10G Pa;A=π(0.02mm/2)2
ΔD=εshear×D0
εshear=εaxial×V
εaxial=σaxial / E
σaxial=N/A
You seem to be using the given Young's modulus as though it is the applied stress. They happen to have the same dimension, pressure, but they are not the same thing. Specifically, the modulus is that stress which would, in theory, double the wire's length.billy722 said:stressShear= E×I
R=0.01mm,E=10GPa, I0= (π/4)×(0.01×10(-3))4=7.85 zm4
Stressshear=(10×109×7.85×10-21)
=78.5p Pa
Shear modulus=E/[2(1+V)] = 10G/[2(1+0.25)]=4GPa
Shear modulus= Stressshear/εshear
εshear=78.5p/4G=19.625z
ΔD=εshear×D0
=19.625z×0.02m
=0.3925y m
Is it right?
billy722 said:Stressshear=E×I=F/A
V=strainshear/strainaxial
⇒strainshear=Vχstrainaxial=ΔD/D0
⇒ΔD=D0χVχStrainaxial
=D0χVχ(stressaxial/E)
=D0χVχ(1/E)χ(FχA)
F in shear and F in axial are same?
haruspex said:If the problem statement does not specify an applied load then there is no way to answer it.
haruspex said:If the problem statement does not specify an applied load then there is no way to answer it.
haruspex said:If the problem statement does not specify an applied load then there is no way to answer it.
haruspex said:If the problem statement does not specify an applied load then there is no way to answer it.
Am I getting through?haruspex said:If the problem statement does not specify an applied load then there is no way to answer it.
Stress and strain are two important properties used to describe the mechanical behavior of a fiber. Stress refers to the amount of force applied to a material, while strain refers to the deformation or change in shape of the material as a result of that force.
Stress and strain are directly proportional to each other. This means that as the amount of stress applied to a material increases, the strain or deformation also increases.
Tensile stress and strain occur when a material is stretched or pulled, while compressive stress and strain occur when a material is compressed or pushed together. Both types of stress and strain can affect the behavior of a fiber in different ways.
The stress and strain of a fiber can be influenced by various factors such as the type of material, the length and diameter of the fiber, the amount of force applied, and the temperature of the environment. The properties of the fiber itself, such as its elasticity and strength, also play a role.
Stress and strain are crucial concepts in materials science and engineering, as they help scientists and engineers predict and understand the behavior of a material under different conditions. This knowledge is essential for developing and designing new materials for various applications.