(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 20 kg loudspeaker is suspended 2.0 m below the ceiling by two cables that are each 30 degrees from the vertical. What is the tension in the cables

2. Relevant equations

F=ma

Fx=max

Fy=may

3. The attempt at a solution

a=0

Here is how I solved it but I am not sure if it is right. Also, I don't understand how to use the 2.0 meters given in the problems statements. Anyways, here goes:

Fnetx=Wx + T1x + T2x =max=0

0 + T1 - T2=0

T1sinθ -T2sinθ=0

T1sinθ=T2sinθ

T1=T2

Fnety=wy + T1y + T2y=may=0

-w + T1 + T2=0

(20 * -9.8) + T1cosθ + T2cosθ=0

-196 + (T1 + T2)(cosθ)=0

(T1 + T2)(cosθ)=196

(T1 + T2)=196/cos(30)

(T1 + T2)=226.3

Since T1=T2, then 226.3/2=113 N. Therefore 113 N is the tension for both ropes?

Is this correct?

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# Homework Help: Question about tension?

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