1. The problem statement, all variables and given/known data A 20 kg loudspeaker is suspended 2.0 m below the ceiling by two cables that are each 30 degrees from the vertical. What is the tension in the cables 2. Relevant equations F=ma Fx=max Fy=may 3. The attempt at a solution a=0 Here is how I solved it but I am not sure if it is right. Also, I don't understand how to use the 2.0 meters given in the problems statements. Anyways, here goes: Fnetx=Wx + T1x + T2x =max=0 0 + T1 - T2=0 T1sinθ -T2sinθ=0 T1sinθ=T2sinθ T1=T2 Fnety=wy + T1y + T2y=may=0 -w + T1 + T2=0 (20 * -9.8) + T1cosθ + T2cosθ=0 -196 + (T1 + T2)(cosθ)=0 (T1 + T2)(cosθ)=196 (T1 + T2)=196/cos(30) (T1 + T2)=226.3 Since T1=T2, then 226.3/2=113 N. Therefore 113 N is the tension for both ropes? Is this correct?