- #1
aikismos
- 145
- 34
Just to double check, but if one wanted to, like in partial fraction decomposition, associate literal coefficients of polynomials with corresponding unknowns on the other side of the equation, the justification for this action is the definition of equality of polynomials?
EDIT: I know this isn't true. Let's see, ## a - b = 2 ## is as far as it can be reduced.
## 3x^2 + bx = ax^2 + 5x \rightarrow a = 3, b = 5 ##
Another related question is how do I express symbolically that in:
## P(x) = ax^2 + bx ##
P(x) has no constant term?
I'm kinda groping around for a rigorous way to express and justify the pairing of coefficients if you were to write them as two equivalent n-tuples.
EDIT: I know this isn't true. Let's see, ## a - b = 2 ## is as far as it can be reduced.
## 3x^2 + bx = ax^2 + 5x \rightarrow a = 3, b = 5 ##
Another related question is how do I express symbolically that in:
## P(x) = ax^2 + bx ##
P(x) has no constant term?
I'm kinda groping around for a rigorous way to express and justify the pairing of coefficients if you were to write them as two equivalent n-tuples.
Last edited: