1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

I Question about the physics term "work"

  1. Dec 27, 2017 #41


    User Avatar
    Science Advisor

    Not really. The sign depends for which object the work is computed and in which frame of reference.
  2. Dec 27, 2017 #42
    So when a body is being dragged forward by a moving boundary in the direction it is already moving, the work that the moving boundary is doing on the body is negative?
  3. Dec 27, 2017 #43


    User Avatar
    Science Advisor

    One can salvage the truth of this claim by considering the kinetic friction between two objects, A and B that are sliding past one another. The sum of the work done by A on B plus the work done by B on A will be negative.
  4. Dec 27, 2017 #44

    Mister T

    User Avatar
    Science Advisor
    Gold Member

    A scalar can be positive or negative.

    Perhaps you are confusing vector magnitudes with vector components. The magnitude of a vector is never negative, but the component of a vector can be either negative or positive. In the expression for kinetic energy, ##\frac{1}{2}mv^2##, ##v## is a vector magnitude, the speed, and as such can never be negative. In an equation such as ##v=v_o+at##, ##v## is actually a vector component and as such can either be negative or positive. This last bit is a source of confusion for students, which is why a few authors have taken to writing equations like that as ##v_x=v_{ox}+a_xt## to make that distinction clear.
  5. Dec 28, 2017 #45
    No. Only 2500J of work was done. Idealizing this situation, the person pushing the dresser is the source of the force and is fixed to the earth during the pushing. Consider the pushing to be a series of pushes in place, feet fixed arms acting as a spring for each push with steps taken by the person between pushes, ignoring the energy used to take the steps. The person does work on the dresser as we all agree. The reaction force of the dresser on the person does no work because during the pushing the person does not move. (ideally) because he is firmly connected to the immovable earth If the person is loosely coupled to the earth as when say standing on a slippery surface then when he pushes he will move backwards as the dresser moves forward. The energy needed to do the work is divided unevenly between the person and the dresser if the dresser moves more forward than the person moves backwards.

    Regarding the sign of work I have always interpreted it when negative as the work done on an object in opposition to its motion as the brakes on an auto or friction on a sliding object. The force direction and displacement are in opposite directions.
  6. Dec 28, 2017 #46


    User Avatar
    Science Advisor

    If you are treating the arms as springs and ignoring the legs then the energy needed to do the work comes 100% from the arms.
  7. Dec 28, 2017 #47
    You can couple the legs and arms through the trunk if you want and consider the person as a spring. Real situations are difficult to model exactly by the point was to look at it simplistically to see the basic physics in play.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted

Similar Threads for Question physics term Date
I MRI physics question Mar 13, 2018
B Question on classical electron radius Jan 2, 2018
B General Physics Question -- Max height of a projectile Jun 25, 2017