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Question about Voltage drop

  1. Aug 12, 2016 #1
    • ★★ members must not remove essential diagrams after receiving help on these forums ★★
    Screen+Shot+2016-08-13+at+1.45.47+PM.png
    https://puu.sh/qzv6o/5abc45494b.png

    I was under the impression that voltage drop was the same in parallel which would make it the power supply, but apparently not? Any insight would help. I know this isn't a hard a question, I'm just horrible at physics.
     
    Last edited by a moderator: Aug 13, 2016
  2. jcsd
  3. Aug 12, 2016 #2

    Student100

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    Can you reword this? I think I know what you're saying, but I don't think you're saying it very well.

    The same in parallel compared to what? To series? No, but I don't think this is what you meant. I think you meant it's the same as the power supply voltage. Is this correct?
     
  4. Aug 12, 2016 #3
    My apologies. Yes, the same as the power supply. And if that isn't the case, at least the same in each of the resistors. But the answer doesn't seem to be correct? I'm lost on how I should go about calculating the voltage drop with the provided information.
     
  5. Aug 12, 2016 #4

    Student100

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    Say I pulled out what I can only assume is an ammeter, breaking the circuit there? Would current still flow?
     
    Last edited by a moderator: Aug 13, 2016
  6. Aug 12, 2016 #5

    NascentOxygen

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    Thread reopened.
     
    Last edited: Aug 13, 2016
  7. Aug 19, 2016 #6
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