# Question form Peskin Schroeder

1. Aug 6, 2007

### Sombrero

Dear PF,

I have one question form Peskin Schroeder....could you pls help me
It is very simple question...
Since I dont know how to write formulas here I put my question in attachment.

Thank you very much.

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2. Aug 12, 2007

### dextercioby

Well just use the fact that $pk=m\omega$ and $pk'=m\omega'$ plus the Compton relation

$$\frac{1}{\omega}-\frac{1}{\omega'}=\frac{\cos\theta - 1}{m}$$

And you'll get that -sin^2 after using a bit of trigonometry.