ok iv tried this like 2 times and im still not geting it(adsbygoogle = window.adsbygoogle || []).push({});

Q> suppose that h(x)=f(x+1) and that the line tangent to the graph of f at the point (2,f(2)) is described by the equation y = 3x-4.

a) evaluate h(1)

b) evaluate h'(1)

heres what i know and did.

i under stand that for h(1) i just plug in 1 for h(x) = f(x+1) and get f(2)

but for h'(1) im so posed to find the slope at h(1) and so i figured that since y=3x-4 is the tangent line that touches h(x)=f(x+1) at the points (2,f(2)), the functions are equal and have the same (x,y) and so i was trying to find the slope but im not sure what my cord nets are to do the change in y over change in x, and the point that im so posed to use to find the derivative of h(1)

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# Homework Help: Question help please

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