After reading a bit on classical mechanics, I decided to set myself a somewhat simple to most, but quite challenging to me question. I managed to come to a final answer. I think I may have gone a little wrong, but I'd appreciate any help or guidance. Can anyone confirm if I'm right or wrong? N.B: I didn't include the static coefficient of friction as I don't know how to use both in the same problem. However, I believe I would be right to say that it shouldn't affect the answer...? Okay, so the question I set myself is; If a box of mass 10 KG is put at the top of a ramp at 60 degrees and with a hypotenuse of length 6m, what will be the velocity of the box at the bottom of the ramp? (I included friction into the problem. I used a hypothetical kinetic coefficient of friction of 0.5). So the known variables are: Ramp angle = 60 degrees. Box mass = 10 KG Kinetic Coefficient of friction = 0.5 Length of ramp (hypotenuse, not adjacent) = 6m So here's what I did... 1) I found the force of gravity acting along the ramp. I found the force of gravity by doing the following.. 9.81*COS(90-60) = 8.5 m/s^2. Since F=ma, I found the component of gravity acting along the ramp to be 85N. 2) Next I found the same for friction. Since friction is the normal force times by the coefficient of friction, i did 85 (normal force) times by 0.5 (coefficient). This comes to 42.5. 3) To find the net force, I did the force of gravity (85N) minus the force of friction (42.5N). This comes to a total of 42.5N of force down the ramp. 4) Since F=ma, I found the acceleration to be 4.25 m/s^2. 5) With the formula v^2=2as, I found that 2*4.25*6=51. Finally, I found the square root of 51 to be 7.14. This shows that the velocity at the bottom of the ramp is 7.14 m/s. B.T.W, can anyone confirm whether this type of question is likely to come up in my GCSE next year? I want to get a solid idea on all of the topics while I can.