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Hey everybody..
I got this space geometry question that had me stumped.. Please help me out.. Here goes:
ABCD is a parallelogram. The plane π was drawn passing through the diagonal AC.
If DE was perpendicular to π, BF was perpendicular to π.
Prove that BF = DE
please see the attached drawing
I got this space geometry question that had me stumped.. Please help me out.. Here goes:
ABCD is a parallelogram. The plane π was drawn passing through the diagonal AC.
If DE was perpendicular to π, BF was perpendicular to π.
Prove that BF = DE
please see the attached drawing
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