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A function is g(x) = 2 (x-3) ^2 + 4

Find the range when 0 <= x <= 6

steps i took:

0 <= x <=6

0-3 <= x-3 <= 6-3

-3^2 <= (x-3)^2 <= 3^2

9 <= (x-3)^2 <= 9

22 <= 2 (x-3)^2 + 4 <=22

:: what did i do wrong?

correct answer is:

{ y | 4 <= y <= 22 }

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case#2

A certain function is defined as f(x)=x^2 + 3

if -3 <= x <=3, determine the range

i got {y | 3 <= y <= 9 }

correct answer is:

{y | 3 <= y <= 12}

Thanks in advance

Preet

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# Homework Help: Question (math - inequalities)

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