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Question of differentiation

  1. Apr 19, 2010 #1
    I am confuse with this:

    [tex]Let\;\; t=jx \;\;,\;\; j =\sqrt{-1}[/tex]

    [tex] \Rightarrow \frac{dt}{dx}=j[/tex]

    But if I use [tex]t^2=-x^2 \;\Rightarrow\; 2t\frac{dt}{dx}=-2x[/tex]

    [tex]\Rightarrow \frac{dt}{dx}=-\frac{x}{t}[/tex]

    What is wrong?
  2. jcsd
  3. Apr 20, 2010 #2


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    Homework Helper

    sub back t=jx, and then multiply by j/j
  4. Apr 20, 2010 #3

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