The equation for current in series is I1=12=13 as the charges remain constant as it passes through the circuit regardless of the resistances of the resistors. i1 being the current before the resistor, i2 being the current after resistor 1 and i3 being the current after the last (2nd) resistor before going back to the battery. However, I=Q/T and since the resistors have resistance, the current will move slower through it. Wont this affect the current? why the current remains constant throughout the circuit (i1=i2=i3)?? can someone explain to me please?