i have to design a vehicle that will accelerate up a 1/8 gradient hill to 11.11m/s in 15s(adsbygoogle = window.adsbygoogle || []).push({});

i need the effort required and wheel torque.

mass = 170kg

rolling resistance = 50N/t (0.05N/kg)

air resistance = 13.6N

g = 9.81m/s^2

i have calculated:

a = 11.11*(1/15) = 0.74m/s^2

theta = 7.18 deg

sin theta = 0.125 deg

so i have the effort as:

E = ma+mgsin_theta+Froll+Fair

E = 125.8+(170*9.81*0.125)+0.05+13.6

E = 347.9125N

is E the torque i need at the wheels?

if not how would you go about working it out.

i tried with a motor of 40N, wheel radius of 0.2m and gear ratio of 10:1

i worked it out like this.

axle torque = 40*10 = 400N

so to find the torque at the wheel do i divide the axle torque by wheel radius

400/0.2 = 2000 that seems wrong to me??

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# Question on effort

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