i have to design a vehicle that will accelerate up a 1/8 gradient hill to 11.11m/s in 15s i need the effort required and wheel torque. mass = 170kg rolling resistance = 50N/t (0.05N/kg) air resistance = 13.6N g = 9.81m/s^2 i have calculated: a = 11.11*(1/15) = 0.74m/s^2 theta = 7.18 deg sin theta = 0.125 deg so i have the effort as: E = ma+mgsin_theta+Froll+Fair E = 125.8+(170*9.81*0.125)+0.05+13.6 E = 347.9125N is E the torque i need at the wheels? if not how would you go about working it out. i tried with a motor of 40N, wheel radius of 0.2m and gear ratio of 10:1 i worked it out like this. axle torque = 40*10 = 400N so to find the torque at the wheel do i divide the axle torque by wheel radius 400/0.2 = 2000 that seems wrong to me??