- 370

- 1

there have been a thread going on about worst/best notations. as i said there, i was confused with [tex]f^{-1}(x)[/tex] when i first came across it in high school. i thought [tex]f^{-1}(x)[/tex] is the same as [tex]{1}\over{f(x)}[/tex]

but now i am wondering, is there any function for which

[tex]f^{-1}(x)[/tex] = [tex]{1}\over{f(x)}[/tex]?

but now i am wondering, is there any function for which

[tex]f^{-1}(x)[/tex] = [tex]{1}\over{f(x)}[/tex]?

Last edited: