- #1
murshid_islam
- 457
- 19
there have been a thread going on about worst/best notations. as i said there, i was confused with [tex]f^{-1}(x)[/tex] when i first came across it in high school. i thought [tex]f^{-1}(x)[/tex] is the same as [tex]{1}\over{f(x)}[/tex]
but now i am wondering, is there any function for which
[tex]f^{-1}(x)[/tex] = [tex]{1}\over{f(x)}[/tex]?
but now i am wondering, is there any function for which
[tex]f^{-1}(x)[/tex] = [tex]{1}\over{f(x)}[/tex]?
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