Two cars travel in the same direction along a straight highway, one at a constant speed of 55 mi/h and the other at 70.0 mi/h. How far must the faster car travel before it has a 15 minute lead on the slower car?
average velocity=change of position/change in time
The Attempt at a Solution
Change of position= equals average velocity multiplied by change in time
I need to know what distance the slower car covers in 15 minutes.
55mph*.25h= 13.75 miles. In other words, if the faster car was 13.75 miles ahead, it would take me 15 minutes or .25 hours to catch up.
This is what I think the answer should be, but according to the answer sheet, it's actually 64 miles. What did I miss?