energy from electron passing between 2 electrodes, and calc. the freq of the elec. 1. The problem statement, all variables and given/known data Part 1: The difference in potential between the cathode and anode of a spark plug is 17800 V. What energy does the electron give up as it passes between the electrodes? Answer in units of J. Part 2: One fourth of the energy given up by an electron is converted into radiation in the form of a single photon. What is the frequency of the radiation? Answer in units of Hz. 2. Relevant equations v=i*r? Q = Δmc2 E=hf? planck's constant=6.62607 × 10^-34 J · s c² =931.5 MeV/u 1 eV=1.602×10−19 J idk what else is needed sry 3. The attempt at a solution I'm not sure how to begin this problem, but my attempts are listed below Pt.1: E= (1.602×10−19 J)(17800V)=2.85156 x 10^-15 Pt 2: E=hf [(1/4)*(2.85156 x 10^-15)]/(6.62607 × 10^-34 J · s) =f <<<<-not sure f=1.075886612 x 10^18 Hz??