Question on nuclear/quantum mech. unit of physics, please help its due 10pm tonight

  • #1
energy from electron passing between 2 electrodes, and calc. the freq of the elec.

Homework Statement


Part 1:
The difference in potential between the cathode and anode of a spark plug is 17800 V.
What energy does the electron give up as it
passes between the electrodes?
Answer in units of J.

Part 2:
One fourth of the energy given up by an electron is converted into radiation in the form of
a single photon.
What is the frequency of the radiation?
Answer in units of Hz.

Homework Equations


v=i*r?
Q = Δmc2
E=hf?
planck's constant=6.62607 × 10^-34 J · s
c² =931.5 MeV/u
1 eV=1.602×10−19 J
idk what else is needed sry

The Attempt at a Solution



I'm not sure how to begin this problem, but my attempts are listed below
Pt.1: E= (1.602×10−19 J)(17800V)=2.85156 x 10^-15
Pt 2: E=hf
[(1/4)*(2.85156 x 10^-15)]/(6.62607 × 10^-34 J · s) =f <<<<-not sure
f=1.075886612 x 10^18 Hz??
 
Last edited:

Answers and Replies

  • #2


never mind i got it answered
turns out my process was correct
 

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