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Question on Projectile Motion

  1. Feb 20, 2006 #1
    A dart is thrown horizontally with an initial speed of 11 m/s toward point P, the bull's-eye on a dart board. It hits at point Q on the rim, vertically below P, 0.19 s later. (a) What is the distance PQ? (b) How far away from the dart board is the dart released?

    Is part a basically asking for the vertical motion?

    Thanks.
     
  2. jcsd
  3. Feb 20, 2006 #2

    Doc Al

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    Staff: Mentor

    Right. In other words: How far does the dart fall during its flight?
     
  4. Feb 20, 2006 #3
    Just confirming that my formula is right here, wouldn't that be obtained by:

    y = 11sin(0).19 - 4.9(.19)^2?
     
  5. Feb 20, 2006 #4

    Doc Al

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    Staff: Mentor

    Right. That gives the y-coordinate of the dart when it hits the board.
     
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