Hello everyone, I'm trying to do a question on projectile motion, and I think the first part I have done right, but after that it is going downhill for me. Here is the question and my work: A shotputter releases the shot some distance above the level ground with a velocity of 12.0m/s @51 degrees above the horizontal. The shot hits the ground 2.08 seconds later. You can ignore air resistance. (a) What are the components of the shot's acceleration while in flight? (b) What are the components of the shot's velocity at the beginning and at the end of its trajectory? (c) How far did she throw the shot horizontally? (d) Why does the expression for R (R=(Vi^2sin(2)(initial angle))/g) not give the correct angle answer for part c? (e) How high was the shot above the ground when she released it. (a) For this part, you know that all of the acceleration once the shot leaves her hand is due to gravity, therefore her Ax=0 and her Ay=-9.81m/s^2 (b)For this part I just used V(x)=Vi(costheta)= (12.0cos51)=7.55m/s, and V(y)=Vi(sintheta)= 9.33m/s. At the beginning of the trajectory the velocities should be the same as at the end of the trajectory, expect the y component of velocity will at this point be negative, as it is travelling downwards. (c) x=(vicostheta)t = (12.0cos51)2.08s=15.7m (d) For this part I think that the above equation won't work because you are dealing with y values when you are wanting to find horizontal values. Not to mention the fact that you are starting at a y value above the origin (shot is released above the ground). (e) This is where most of my troubles start. Even if my above answers are not correct, at least I could figure out a value for them. I have no idea how to do this one.