- #1

- 8

- 0

h =m

my question is what formula should i use? I've been using 1/2mv^2+1/2lw^2=mgh...but i haven't been getting the right answer...if anyone knows has a hint that would help i would like to use it :)

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- Thread starter lefthand
- Start date

In summary, the conversation discusses using the formula 1/2mv^2+1/2lw^2=mgh to calculate the maximum height a mass will reach after a wheel is released and starts slowing down due to the downward tension of a cord. The formula is based on conservation of energy, but some possible mistakes to check for include using the wrong mass for calculating I, not accounting for the distribution of mass in the wheel, and using the wrong radius for calculating I or relating v and ω.

- #1

- 8

- 0

h =m

my question is what formula should i use? I've been using 1/2mv^2+1/2lw^2=mgh...but i haven't been getting the right answer...if anyone knows has a hint that would help i would like to use it :)

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- #2

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- 185

1. When you calculate I, do you use the mass of the

2. Is the wheel like a solid disk, or is most of its mass in the rim? That will affect what

3. Sometimes a problem tells you the

If you didn't make any of those mistakes I listed, then please post your work.

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