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Homework Help: Question (redirected)

  1. Dec 10, 2009 #1
  2. jcsd
  3. Dec 10, 2009 #2

    kuruman

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    You use spherical coordinates, but without boundary conditions, you will not be able to find the potential, so you need to specify them.

    Barring time-dependent boundary conditions, "conducting" means that the entire sphere is an equipotential.
     
  4. Dec 10, 2009 #3
    So, my solution will satisfy:

    [tex]\nabla^{2}\Psi = 0[/tex]

    [tex]\Psi = \sum a \Psi[/tex]

    Should I assume there will be no potential outside the spheroid (or whatever)? And do the boundary conditions determine what particular solution (there is a table of different ones) it will be?
     
  5. Dec 10, 2009 #4

    kuruman

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