Solving Physics Homework: Question Redirected

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In summary, the conversation is discussing the use of spherical coordinates and boundary conditions in finding the potential for a conducting sphere. It is mentioned that without boundary conditions, the potential cannot be determined. The solution will satisfy a Laplace equation and may have multiple possible solutions depending on the specified boundary conditions. A reference for further understanding is also provided.
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  • #2
You use spherical coordinates, but without boundary conditions, you will not be able to find the potential, so you need to specify them.

Barring time-dependent boundary conditions, "conducting" means that the entire sphere is an equipotential.
 
  • #3
So, my solution will satisfy:

[tex]\nabla^{2}\Psi = 0[/tex]

[tex]\Psi = \sum a \Psi[/tex]

Should I assume there will be no potential outside the spheroid (or whatever)? And do the boundary conditions determine what particular solution (there is a table of different ones) it will be?
 

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