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1. Dec 10, 2009

Void123

2. Dec 10, 2009

kuruman

You use spherical coordinates, but without boundary conditions, you will not be able to find the potential, so you need to specify them.

Barring time-dependent boundary conditions, "conducting" means that the entire sphere is an equipotential.

3. Dec 10, 2009

Void123

So, my solution will satisfy:

$$\nabla^{2}\Psi = 0$$

$$\Psi = \sum a \Psi$$

Should I assume there will be no potential outside the spheroid (or whatever)? And do the boundary conditions determine what particular solution (there is a table of different ones) it will be?

4. Dec 10, 2009