# Question (redirected)

#### Void123

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#### kuruman

Homework Helper
Gold Member
You use spherical coordinates, but without boundary conditions, you will not be able to find the potential, so you need to specify them.

Barring time-dependent boundary conditions, "conducting" means that the entire sphere is an equipotential.

#### Void123

So, my solution will satisfy:

$$\nabla^{2}\Psi = 0$$

$$\Psi = \sum a \Psi$$

Should I assume there will be no potential outside the spheroid (or whatever)? And do the boundary conditions determine what particular solution (there is a table of different ones) it will be?

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