When an a.c. flows in a resistor,the mean power dissipated is P.If the frequency of the a.c. is doubled with the same value of peak voltage,what id the average power dissipated now ?(adsbygoogle = window.adsbygoogle || []).push({});

My solution :

P = (I_rms)^2 R

I assume that as the peak voltage remains the same and the mean power value doesn't influenced by the frequency of the a.c. , so the mean power remains the same, that is P.

Is my assumption right ?I hope that someone will help me figure out.Do comment if I have any error in my assumption.Thanks for anybody that spend some time on this question.

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# Homework Help: Question regarding alternating current

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