Question regarding Binomial expansion.

  • #1

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I have my question and my problem in the attachment that followed.
 

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  • #2
quasar987
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By "fourth root of 19/21", they mean the quantity [itex](19/21)^{1/4}[/itex].

Like in your other question, you would like to find the x meeting the condition "x^3 is ignorable" and such that

[tex]\frac{1-x}{1+x}=\frac{19}{21}[/tex]

You will find that x easily by solving this last equation for x.

Then, with n=1/4, your polynomial formula gives you the wished approximation.
 
  • #3
Thanks for your help.I think I now can understand with what the question want.
 

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