I have my question and my problem in the attachment that followed.
Jan 1, 2005 #1 Sanosuke Sagara 102 0 Main Question or Discussion Point I have my question and my problem in the attachment that followed. Attachments Doc5.doc 18 KB Views: 101
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Jan 1, 2005 #2 quasar987 Science Advisor Homework Helper Gold Member 4,773 8 By "fourth root of 19/21", they mean the quantity [itex](19/21)^{1/4}[/itex]. Like in your other question, you would like to find the x meeting the condition "x^3 is ignorable" and such that [tex]\frac{1-x}{1+x}=\frac{19}{21}[/tex] You will find that x easily by solving this last equation for x. Then, with n=1/4, your polynomial formula gives you the wished approximation.
By "fourth root of 19/21", they mean the quantity [itex](19/21)^{1/4}[/itex]. Like in your other question, you would like to find the x meeting the condition "x^3 is ignorable" and such that [tex]\frac{1-x}{1+x}=\frac{19}{21}[/tex] You will find that x easily by solving this last equation for x. Then, with n=1/4, your polynomial formula gives you the wished approximation.
Jan 1, 2005 #3 Sanosuke Sagara 102 0 Thanks for your help.I think I now can understand with what the question want.