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Question regarding Binomial expansion.

  1. Jan 1, 2005 #1
    I have my question and my problem in the attachment that followed.
     

    Attached Files:

  2. jcsd
  3. Jan 1, 2005 #2

    quasar987

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    By "fourth root of 19/21", they mean the quantity [itex](19/21)^{1/4}[/itex].

    Like in your other question, you would like to find the x meeting the condition "x^3 is ignorable" and such that

    [tex]\frac{1-x}{1+x}=\frac{19}{21}[/tex]

    You will find that x easily by solving this last equation for x.

    Then, with n=1/4, your polynomial formula gives you the wished approximation.
     
  4. Jan 1, 2005 #3
    Thanks for your help.I think I now can understand with what the question want.
     
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