1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Question regarding PH-value!

  1. Nov 23, 2004 #1
    I have calculated the PH-value for this following solution:

    100 mL 0,102 M HCL and 100 mL 0,0780 M NaOH.

    To calculate the pH in the this solution first I must calculate the number of moles [itex]n_{[H_3O^+]}[/itex].

    [itex]n_{[H_3 O^{+}]} = 0,100 L \cdot 0,0102 \ mol/L + 0,100 L \cdot 0,0780 mol/L = 0,018 mol[/itex]

    This means that [itex][H_3 O^{+}] = \frac{0,018 mol}{0,200 L} = 0,09 mol/L[/itex]

    pH for the solution is then [itex]pH = \textrm{-log}(0,09) = 1,05[/itex]

    I would appriciate if somebody would look at my calculation and then tell me if its accurate ??

    Many thanks in advance.

    Sincerely

    Fred
     
  2. jcsd
  3. Nov 24, 2004 #2
    No. of moles of HCl in 100mL, 0.102 M soln. = 0.0102
    No. of moles of NaOH in 100mL, 0.078 M soln. = 0.0078

    So, a neutralization takes place and the number of moles of HCl that remain = 0.0102-0.0078=0.0024.

    The concentration of H+ ions is 0.0024/0.200 = 0.012M

    So, pH=-log(0.012)=1.92


    spacetime
    www.geocities.com/physics_all
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Question regarding PH-value!
Loading...