# Question which has me stumped

1. Mar 8, 2008

### rushil01

Hey guys, im currently studying Engieering in Australia and there is one question which was given to us which i have no idea on how to complete and i was wondering if you guys could give me a hand with it;

What is the equilibrium seperation of HCl? ITs measured electric dipole moment is 3.60 x 10^-30C.m and the percentage of covalent bonding in HCl is 82.5%

ANy help would be greatly appreciated. Thanx

2. Mar 9, 2008

### lightarrow

$$r =\ \mu_D/q\cdot P\ =\ 6.25\cdot10^{18}\ \mu_D/P\ =\ 6.25\cdot10^{18}\cdot3.6\cdot10^{-30}/0.825\ =\ 2.73\cdot10^{-11}\ m\ =\ 27.3\ pm$$

3. Mar 16, 2008

### mate1000

What are those formulas you came up with and where did 6.25*10^18 come from.
Thanks

4. Mar 16, 2008

### rushil01

i got my lecturer to do it and he used the formula p=qd. I'll post the full working out when i have a little more time