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Homework Help: Question which has me stumped

  1. Mar 8, 2008 #1
    Hey guys, im currently studying Engieering in Australia and there is one question which was given to us which i have no idea on how to complete and i was wondering if you guys could give me a hand with it;

    What is the equilibrium seperation of HCl? ITs measured electric dipole moment is 3.60 x 10^-30C.m and the percentage of covalent bonding in HCl is 82.5%

    ANy help would be greatly appreciated. Thanx
     
  2. jcsd
  3. Mar 9, 2008 #2
    [tex]r =\ \mu_D/q\cdot P\ =\ 6.25\cdot10^{18}\ \mu_D/P\ =\

    6.25\cdot10^{18}\cdot3.6\cdot10^{-30}/0.825\ =\ 2.73\cdot10^{-11}\ m\ =\ 27.3\ pm[/tex]
     
  4. Mar 16, 2008 #3
    What are those formulas you came up with and where did 6.25*10^18 come from.
    Thanks
     
  5. Mar 16, 2008 #4
    i got my lecturer to do it and he used the formula p=qd. I'll post the full working out when i have a little more time
     
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