- #1
Gear300
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Homework Statement
I was doing a problem with normal force on an inclined plane and found the normal force by finding the y-component of the gravity vector. Then I also found that if I find the components of the normal force, I can also get another answer.
-How are the 2 different equations available for the normal force the same
Homework Equations
Fg = mg
Fgy = -mgcos(theta)
Fny = Fncos(theta)
The Attempt at a Solution
Fgy = -mgcos(theta)
Fn - mgcos(theta) = 0 'movement along plane; not vertically
Fn = mgcos(theta)
Fny = Fncos(theta)
Fncos(theta) - mg = 0 'movement along plane; not vertically
Fn = mg/cos(theta)
I got 2 equations for Fn; Fn = mgcos(theta), Fn = mg/cos(theta)...I'm not understanding how the 2 are the same; can anyone help
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