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## Homework Statement

I was doing a problem with normal force on an inclined plane and found the normal force by finding the y-component of the gravity vector. Then I also found that if I find the components of the normal force, I can also get another answer.

-How are the 2 different equations available for the normal force the same

## Homework Equations

Fg = mg

Fgy = -mgcos(theta)

Fny = Fncos(theta)

## The Attempt at a Solution

Fgy = -mgcos(theta)

Fn - mgcos(theta) = 0 'movement along plane; not vertically

Fn = mgcos(theta)

Fny = Fncos(theta)

Fncos(theta) - mg = 0 'movement along plane; not vertically

Fn = mg/cos(theta)

I got 2 equations for Fn; Fn = mgcos(theta), Fn = mg/cos(theta)...I'm not understanding how the 2 are the same; can anyone help

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