# Question with the Right Answer

• queenspublic
In summary, the conversation discusses Atwood's machine, which consists of two blocks connected by a cord over a frictionless pulley. The masses of the blocks are given as 1.30 kg and 2.80 kg. The conversation then focuses on finding the magnitude of the acceleration of the blocks, which is eventually determined to be 3.58 m/s^2. The solution involves drawing a free body diagram, calculating the net force on the system, and using the equation F=ma to solve for the acceleration.
queenspublic

## Homework Statement

A figure shows two blocks connected by a cord that passes over a frictionless pulley. The arrangement is known as Atwood's machine. Block 1 has mass m1 = 1.30 kg; block 2 has mass m2 = 2.80 kg.

Sorry, no picture.

What is the magnitude of the acceleration of the blocks?

## Homework Equations

T = 1.3a + 12.7 N
T = -2.8a + 27.4 N

## The Attempt at a Solution

The answer is 3.58 m/s^2 but why and how?

The easiest way to start here is probably to draw a free body diagram of the system. Have you done that?

Once you have that, figure out the net force exerted on the system.

Well. that's what I kind of did when I got those two equivalent equations.

For block two, we assumed that acceleration is moving downward.

Does anyone know how to get 3.58?

Never mind. I got it!

You set them equal to each other and solve for a.

As you probably know now, once you have the net force on the system (which should work out to be |M1*g-M2*g|), you set the mass equal to the sum of the masses of the two blocks, and then solve for A using F=MA.

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