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Questions about limits.

  • Thread starter kiss89
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  • #1
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I have 2 questions about limits :

1)Evaluate : lim as x approaches infinity for
(3x-4-4x^2) / (x^2 -16)

2)Evaluate: lim as x approaches -27 for
(27+x) / ( 7/2 + 3 )

thank u.
 

Answers and Replies

  • #2
JasonRox
Homework Helper
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I have 2 questions about limits :

1)Evaluate : lim as x approaches infinity for
(3x-4-4x^2) / (x^2 -16)

2)Evaluate: lim as x approaches -27 for
(27+x) / ( 7/2 + 3 )

thank u.
If you show us some work, we will be glad to help you.
 
  • #3
13
0
Sorry about that.....heres my work
http://img88.imageshack.us/img88/9971/img002sy9.png [Broken]
 
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  • #4
492
1
I have 2 questions about limits :

1)Evaluate : lim as x approaches infinity for
(3x-4-4x^2) / (x^2 -16)

2)Evaluate: lim as x approaches -27 for
(27+x) / ( 7/2 + 3 )

thank u.
for #1, in order to find the limit as x approaches infinity you need to divide the numerator/denominator by the highest power of x in the denominator, in this problem it would be x^2.
Doing this you'd end up with some 1/x's or x^n times some constant (1,2,3,...) which =0 when you take their limit as x approaches infinity

for #2, lim as x approaches a for f(x) = f(a) IF a is in the domain of f
 
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  • #5
312
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For #2, when you plug -27 in you get a number over a nonzero. That means the limit equals the value of the function, in this case, 0
 
  • #6
13
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what about Q.1 i still dont understand how to solve it using infinity???
 
  • #7
312
0
In the limit, only the highest degree matters. Because the numerator and denominator have the same degree, the function will have a limit (horizontal asymtote) approaching infinity. Divide the coefficient of the numerator by the coefficient of the denominator and you have all thats left when x is big. Your post is different from your work, but either way the answer should be apparent in 2 seconds
 

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