(adsbygoogle = window.adsbygoogle || []).push({}); Question 1:

1. The problem statement, all variables and given/known data

If E_{f}=E_{v}find the probability of a state being empty at E=E_{v}-KT

F(E)=1 Divided by 1+(exp(E-E_{f})/KT)

k=8.62*10^{-5}eV/k

2. Relevant equations

3. The attempt at a solution

when i used this equation to find the probability:

F(E)=1 Divided by 1+(exp(E-E_{f})/KT) the final answer was wrong and the model answer used F(E)=1- [1 Divided by 1+(exp(E-E_{f})/KT)]

why?

Question 2:

1. The problem statement, all variables and given/known data

Calculate the temperature at which there is a 1 percent probability that a state 0.30 eV below the fermi level will be empty of an electron

F(E)=1- [1 Divided by 1+(exp(E-E_{f})/KT)]

F(E)=0.01

E-E_{f}=-0.03 eV

k=8.62*10^{-5}eV/k

2. Relevant equations

3. The attempt at a solution

F(E)=1- [1 Divided by 1+(exp(E-E_{f})/KT)]

0.01=1- [1 Divided by 1+(exp(-0.03)/KT)]

1.01=1 Divided by 1+(exp(-0.03)/KT)

100/101=1+(exp(-0.03)/KT)

-1/101=(exp(-0.03)/KT)

ln(-1/101)=-0.03/KT

so i stopped here and didn't know what to do

Question 3:

1. The problem statement, all variables and given/known data

Assume the fermi energy level is exactly in the centre of the band gap energy of a semiconductor at T=300 K (a)calculate the probability that an energy state in the bottom of the conduction band is occupied by an electron for Si, Ge and GaAs. (b) calculate the probability that an energy state in the top of the valence band is empty for Si, Ge and GaAs (Ge: E_{g}=0.66 eV, GaAs:E_{g}=1.42 eV)

F(E)=1 Divided by 1+(exp(E-E_{f})/KT)

2. Relevant equations

3. The attempt at a solution

i just wanna know how to get E and E_{f}for every element to calculate the probability

Question 4:

1. The problem statement, all variables and given/known data

calculate the fermi level of silicon doped with 10^{15}, 10^{17}and 10^{19}phosphorus atoms/cm3 at room temperature assuming complete ionisation. From the calculated fermi level, check if the assumption of complete ionisation is justified for each doping.

(Use n_{i})=9.65*10^{9}atoms/cm^{3}. the ionisation energy for phosphorus in Si 0.045eV )

n=n_{i}exp(E_{f}-E_{i})/KT

p=n_{i}exp(E_{i}-E_{f})/KT

2. Relevant equations

3. The attempt at a solution

what did he mean with 10^{15}, 10^{17}and 10^{19}phosphorus atoms/cm3 does he mean first time doping with10^{15}phosphorus atoms/cm3 and the second time with 10^{17}phosphorus atoms/cm3

and the last time with 10^{19}phosphorus atoms/cm3 ?? and each time calculate electron concentration then holes concentration and then the fermi level with n=n_{i}exp(E_{f}-E_{i})/KT

and what should i do to check if the assumption of complete ionisation is justified for each doping?

Question 5:

1. The problem statement, all variables and given/known data

For n-type silicon sample with 10^{16}phosphorus atoms/cm^{3}donor impurities and a donor level at E_{D}= 0.045 eV, find the ratio of the neutral donor density to the ionised donor density at 77 K where the fermi level is 0.0459 below the bottom of the conduction band.

2. Relevant equations

3. The attempt at a solution

i don't know how to find the ratio of the neutral donor density

**Physics Forums - The Fusion of Science and Community**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Questions about semiconductors

Can you offer guidance or do you also need help?

Draft saved
Draft deleted

Loading...

Similar Threads - Questions semiconductors | Date |
---|---|

Atoms and energy levels question | Mar 23, 2015 |

Questions about metal-semiconductor-metal calculation | Jan 20, 2015 |

Question about semiconductors' holes. | Sep 19, 2011 |

Semiconductor and p-n junction questions | Nov 16, 2009 |

Some semiconductor questions | Mar 10, 2007 |

**Physics Forums - The Fusion of Science and Community**