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Homework Help: Quick and simple Power problem

  1. Feb 22, 2008 #1
    1. In the rope climb, a 68.8kg athlete climbs a vertical distance of 4.74m in 8.70s. What minimum power output was used to accomplish this feat?

    2. Average Power = Work / time

    3. P = mgh/t = 367 W, which is apparently the wrong answer (this is an online course where you input the answer and they tell you if it's correct). I also tried -367W but that doesn't work either. Perhaps this has something to do with the problem asking for minimum power output? Could someone help me out?
  2. jcsd
  3. Feb 22, 2008 #2
    If you use g=9.81 the answer should round to 368 W
  4. Feb 22, 2008 #3
    But is this the right way to do this problem?
  5. Feb 23, 2008 #4


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    Science Advisor
    Homework Helper

    Yes. It's probably a rounding problem as kamerling pointed out.
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