Find the antiderivative of y=tan^2x+sec^2x
The Attempt at a Solution
Seems to be a simple question, but the answer is eluding me no matter what I do. My first try was to replace the tan^2 with sec^2-1, and then factor out a 1/2 from the resulting 2sec^2x-1, but after that I have no idea how to continue. I know that the answer I should wind up with is Y=2tanx-x+C, but have no idea how to go about getting this answer :tongue: Any help would be greatly appreciated, thanks.