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Quick antiderivative question

  1. May 7, 2009 #1
    1. The problem statement, all variables and given/known data
    Find the antiderivative of y=tan^2x+sec^2x


    2. Relevant equations
    N/A



    3. The attempt at a solution
    Seems to be a simple question, but the answer is eluding me no matter what I do. My first try was to replace the tan^2 with sec^2-1, and then factor out a 1/2 from the resulting 2sec^2x-1, but after that I have no idea how to continue. I know that the answer I should wind up with is Y=2tanx-x+C, but have no idea how to go about getting this answer :tongue: Any help would be greatly appreciated, thanks.
     
  2. jcsd
  3. May 8, 2009 #2

    Mark44

    Staff: Mentor

    Hint: d/dx(tan(x)) = sec2(x)
    Every derivative formula gives you an antiderivative formula for free, if look at it the right way.

    I also believe the answer you should end up with is tan(2x) - x + C, which is slightly different from what you show.
     
  4. May 8, 2009 #3
    Ohh I see it now, thanks Mark, and no the answer is correct, as it is what I arrived at as well just now.
    It might have been my mistake writing the question wrong, as it is y=(tanx)^2+(secx)^2. I just wrote it as y=tan^2x+sec^2x assuming people would know that, for example, tan^2x=(tanx)^2. I apologize for that mistake.
     
  5. May 8, 2009 #4

    Mark44

    Staff: Mentor

    Yes, I misread what you wrote.
     
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