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Homework Statement
xy + compliment(xy) = 1
Homework Equations
The Attempt at a Solution
is it true? because x+compliment(x) = 1
maybe its not true...
what if x=1 and y=0 the xy=0 and compliment(xy)=0 then 0+0 != 1Yes. Take ##x + \overline{x} = 1## and rename x to a: ##a + \overline{a} = 1##.
Now set ##a = xy##.
Note, however, that ##\overline{xy} \neq \overline{x} \overline{y}##.
No, complement(xy) = 1what if x=1 and y=0 the xy=0 and compliment(xy)=0 …
i meant compliment(x)compliment(y) = 0Hi ZeroPivot!
(guys, thanks for the compliments, but it's complements! )
No, complement(xy) = 1
xy + compliment(xy) = 1
…
is it true? because x+compliment(x) = 1
maybe its not true...
So you meant, is ##xy + \bar{x}\bar{y} = 1## ?i meant compliment(x)compliment(y) = 0
but thanks.
Because if it were, ##\overline{xy}## would equal ##\bar x \bar y##. In fact it equals ##\bar x + \bar y##.Hi ZeroPivot!
So you meant, is ##xy + \bar{x}\bar{y} = 1## ?
No.