- #1

- 10

- 0

we are asked to find the limit of a function as t approaches zero. the function is:

(sint/2t)i + (e^2t)j + (t^2/e^t)k

why is the answer not just j?

the answer given is 1/2i + j, but I have no idea how that first term came about.

help!

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter don23
- Start date

- #1

- 10

- 0

we are asked to find the limit of a function as t approaches zero. the function is:

(sint/2t)i + (e^2t)j + (t^2/e^t)k

why is the answer not just j?

the answer given is 1/2i + j, but I have no idea how that first term came about.

help!

- #2

shmoe

Science Advisor

Homework Helper

- 1,992

- 1

- #3

- 258

- 1

[tex]\lim_{t{\to}0}\frac{\sin{t}}{t}=1[/tex]don23 said:

we are asked to find the limit of a function as t approaches zero. the function is:

(sint/2t)i + (e^2t)j + (t^2/e^t)k

why is the answer not just j?

the answer given is 1/2i + j, but I have no idea how that first term came about.

help!

edit: i can't remember the diravation at the moment

Last edited:

- #4

- 10

- 0

thank you:) it's been a while...i forgot about l'hopital's rule. thanks again

Share: