- #1

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we are asked to find the limit of a function as t approaches zero. the function is:

(sint/2t)i + (e^2t)j + (t^2/e^t)k

why is the answer not just j?

the answer given is 1/2i + j, but I have no idea how that first term came about.

help!

- Thread starter don23
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- #1

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- 0

we are asked to find the limit of a function as t approaches zero. the function is:

(sint/2t)i + (e^2t)j + (t^2/e^t)k

why is the answer not just j?

the answer given is 1/2i + j, but I have no idea how that first term came about.

help!

- #2

shmoe

Science Advisor

Homework Helper

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- #3

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[tex]\lim_{t{\to}0}\frac{\sin{t}}{t}=1[/tex]don23 said:

we are asked to find the limit of a function as t approaches zero. the function is:

(sint/2t)i + (e^2t)j + (t^2/e^t)k

why is the answer not just j?

the answer given is 1/2i + j, but I have no idea how that first term came about.

help!

edit: i can't remember the diravation at the moment

Last edited:

- #4

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thank you:) it's been a while...i forgot about l'hopital's rule. thanks again

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