- #1
wumple
- 60
- 0
Hi,
If I have the equation
[tex] y' = ax - by [/tex]
where [tex] y = y(t) , x= x(t)[/tex]
and [tex] y' = \frac{dy}{dt} [/tex]
then what is
[tex] \frac {d}{dy} y' = \frac {d}{dy}(ax - by) [/tex]
?
I think it would come out to
[tex] \frac {dy'}{dy} = a \frac {dx}{dt}\frac {dt}{dy} - b [/tex]
Is that right? In general, is y' a function of y or would the first term on the left be 0?
Thanks!
If I have the equation
[tex] y' = ax - by [/tex]
where [tex] y = y(t) , x= x(t)[/tex]
and [tex] y' = \frac{dy}{dt} [/tex]
then what is
[tex] \frac {d}{dy} y' = \frac {d}{dy}(ax - by) [/tex]
?
I think it would come out to
[tex] \frac {dy'}{dy} = a \frac {dx}{dt}\frac {dt}{dy} - b [/tex]
Is that right? In general, is y' a function of y or would the first term on the left be 0?
Thanks!