1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Quick derivative check

  1. Dec 3, 2007 #1
    1. The problem statement, all variables and given/known data
    I want to work out the derivative of xcos(log(x))

    2. Relevant equations

    3. The attempt at a solution

    By using the product rule: and the chain rule;

    cos(logx) - xsin(logx).1/x = cos(log(x)) - sin(log(x))

    Is this right?
  2. jcsd
  3. Dec 3, 2007 #2
    looks right
  4. Dec 3, 2007 #3
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Quick derivative check