Can someone help me factor x^3 + 8? I totally forgot how to do that :S
We must note that this is an expression of the form a^3+b^3=(a+b)(a^2-ab+b^2), where in this case a=x and b=2.
Usually to factor things ,use the remainder and Factor theorem.
Let f(x)=x^3 + 8
try f(1,-1,2,etc) and when you get x=a such that f(a)=0. x-a is a factor of f(x)
For your example; f(-2)=0 so that x+2 is factor of f(x)...you can use synthetic division or long division to get the other factor.
Separate names with a comma.