Quick Faraday equation

[kishanpatel50]

I have this equation and the following values for a transformer

B_max= (V₁)/(4N₁fA)

V₁=10v, i.e. 20v peak-to-peak
N₁=40 turns
f=5000Hz
A=76x10^-6 m²

When i substitute in the voltage, do i use the 10v, or the peak to peak, or would i have to convert to V_rms

 

[Bob S]

the Faraday equation is

V_peak= (2 pi f) B_peak A N

So B_peak= 10/(6.28 f A N) = 0.104 Tesla