a disc drive at rest is powered up and accelerates according to alpha=alpha(i)sin(bt). this lasts for 1.66 seconds after which it no longer accelerates. alpha(i)=506 rad/s^2 b=1.89 radius of disc=3.9cm. After the disc is done spinning up what is the centripetal acceleration of the edge of the disc.
I take this to mean the acceleration at the time of 1.66 because the answer isn't zero. Don't i just plug the time into my equation?