A metallic wire has a diameter of 4.12 mm. When the current in the wire is 8 A, the drift velocity is 5.4*10^-5 m/s. What is the density of free electrons in the metal? I have considered a wire of cross-sectional area A, with current I. V is the drift velocity of the free charges in the conductor and n is the number of charged particles per unit volume. Then the current is given by I = nqva, where q is the magnitude of the charge on a charge carrier. I = 8 n = density?? A = (2.06)^2 * 3.14 v = 5.4 x 10^-5 q = ?? Can someone help me out on the answer for this problem? Thanks!