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Quick Integral Help please

  1. Feb 26, 2008 #1
    1. integral(e^(2x)/[tex]\sqrt{}(e^2^x+1)[/tex])dx and integral(e^(x)/[tex]\sqrt{}(e^2^x+1)[/tex])dx







    3. I tried solvign by letting u=e^x and used trig substitution for [tex]\sqrt{}u^2+1[/tex] where x=tan(theta), d(theta)=sec^2(theta), [tex]\sqrt{}u^2+1[/tex]=sec(theta) but got stuck
     
  2. jcsd
  3. Feb 26, 2008 #2
    [tex]\int\frac{e^{2x}}{\sqrt(e^{2x}+1)}dx[/tex] letting

    [tex]t^{2}=e^{2x}+1=>2tdt=2e^{2x}dx=>tdt=e^{2x}dx[/tex],
    I think you can go from here, right? Similarly try the other, and show a little more work please!
     
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