# Quick integral question

1. May 22, 2005

### ziddy83

ok here is the integral...sorry for the laziness...

integral of dt/(t^4)-25

would this just turn out to be (t^4)-25 since you can bring up the denominator to the top as (something)^-1....then just take the antiderivative...? hope that makes sense

edit: ok that wont work...so I think i need to make a trig sub....so like.....hmm do i let t= sec x?

Last edited: May 22, 2005
2. May 22, 2005

### arildno

Rewrite it to:
$$I=\int\frac{dt}{(t^{2}+5)(t^{2}-5)}$$
and use partial fractions decomposition.

3. May 22, 2005

### whozum

$$\int \frac{dt}{t^4-25} = \int \frac{dt}{(t^2-5)(t^2+5)}$$

edit: tex error

Last edited: May 22, 2005
4. May 22, 2005

### ziddy83

oh ok...cool. Thanks guys

5. May 22, 2005

### GCT

Try factoring out $$t^{4}-25$$. Didn't you learn how to do these type of integrals in lecture (partial fractions)? You'll have to learn how to do such integrals yourself, the process is quite tedious.

6. May 22, 2005

### arildno

That was quick, GCT..

7. May 22, 2005

### GCT

it seems that we were all answering this question at the same time.