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Quick integral question

  1. May 22, 2005 #1
    ok here is the integral...sorry for the laziness...

    integral of dt/(t^4)-25

    would this just turn out to be (t^4)-25 since you can bring up the denominator to the top as (something)^-1....then just take the antiderivative...? hope that makes sense

    edit: ok that wont work...so I think i need to make a trig sub....so like.....hmm do i let t= sec x?
     
    Last edited: May 22, 2005
  2. jcsd
  3. May 22, 2005 #2

    arildno

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    Rewrite it to:
    [tex]I=\int\frac{dt}{(t^{2}+5)(t^{2}-5)}[/tex]
    and use partial fractions decomposition.
     
  4. May 22, 2005 #3
    [tex] \int \frac{dt}{t^4-25} = \int \frac{dt}{(t^2-5)(t^2+5)}[/tex]

    edit: tex error
     
    Last edited: May 22, 2005
  5. May 22, 2005 #4
    oh ok...cool. Thanks guys
     
  6. May 22, 2005 #5

    GCT

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    Try factoring out [tex]t^{4}-25[/tex]. Didn't you learn how to do these type of integrals in lecture (partial fractions)? You'll have to learn how to do such integrals yourself, the process is quite tedious.
     
  7. May 22, 2005 #6

    arildno

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    That was quick, GCT..:wink:
     
  8. May 22, 2005 #7

    GCT

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    it seems that we were all answering this question at the same time.
     
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