Solve a Quick Math Question: How Many Sides in a Polygon w/ 119 Diagonals?

  • Thread starter get_rekd
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Plugging in values:n = \frac{3 \pm \sqrt{9+4(2)(119)}}{2(2)}Simplifying:n = \frac{3 \pm \sqrt{481}}{4}Since we are dealing with number of sides, n must be a positive integer. Therefore, we can disregard the negative solution.n = \frac{3 + \sqrt{481}}{4} \approx 11.03Therefore, the polygon has approximately 11 sides. In summary, a polygon with 119 diagonals has 11 sides.
  • #1
get_rekd
39
0
d=n^2 - 3n / 2

where d = number of diagonals
and n = the number of sides of the polygon.

A polygon has 119 diagonals, how many sides does it have?

119 = n^2 - 3n / 2

I am not sure how to do this? can someone please help?

sorry this isn't physics related
 
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  • #2
An n-sided polygon has this many diagonals:

[tex]\frac{n(n-3)}{2}[/tex]

Solve for [tex]n[/tex].
 
  • #3
get_rekd said:
d=n^2 - 3n / 2

where d = number of diagonals
and n = the number of sides of the polygon.

A polygon has 119 diagonals, how many sides does it have?

119 = n^2 - 3n / 2

I am not sure how to do this? can someone please help?

sorry this isn't physics related
Quadratic Formula
 

What is a polygon?

A polygon is a 2-dimensional shape that is made up of straight lines and has a closed shape. It can have any number of sides, but must have at least three sides.

How many sides does a polygon with 119 diagonals have?

A polygon with 119 diagonals can have a maximum of 16 sides. This is because each additional side adds one more diagonal, so a polygon with 16 sides would have 120 diagonals.

How do you calculate the number of sides in a polygon?

The formula for calculating the number of sides in a polygon is n = (2d + 4) / 3, where n is the number of sides and d is the number of diagonals. In this case, d = 119, so n = (2*119 + 4) / 3 = 80.

What is the relationship between sides and diagonals in a polygon?

The number of diagonals in a polygon is related to the number of sides by the formula d = n(n-3)/2, where d is the number of diagonals and n is the number of sides. This means that as the number of sides increases, the number of diagonals also increases.

Can a polygon have an odd number of sides and 119 diagonals?

Yes, a polygon can have an odd number of sides and 119 diagonals. For example, a polygon with 15 sides would have 119 diagonals. This is because the number of diagonals is determined by the formula d = n(n-3)/2, so as long as the result is an integer, it is possible to have an odd number of sides and 119 diagonals.

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