# Quick Momentum Problem

1. Mar 26, 2009

### lubuntu

1. The problem statement, all variables and given/known data

Two objects have the same momentum, object 1 is heavier than object 2. You bring each to a stop by applying a force of equal magnatude in each case. How does the time to stop each object compare and the distance.

2. Relevant equations
mv=p f=ma etc.

3. The attempt at a solution
I think the the time and distance are equal in both cases because if you solve each quantity for a and v in each case you get an equation where you divide the mass by sum number and set it equal to zero, so the mass cancels out. Just looking to confirm.

2. Mar 26, 2009

### Pengwuino

You can also think of it in the following way with a constant force:

$$F = \frac{{dp}}{{dt}}$$ thus equal forces will result in equal momenta changes over the same period of time in this case.

3. Mar 26, 2009

### Staff: Mentor

What does distance and force relate to? Is that the same for different masses that happen to have the same momentum?