1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Quick ODE question

  1. Apr 26, 2010 #1
    1. The problem statement, all variables and given/known data

    y'' + 9y' = cot(3t)

    2. Relevant equations



    3. The attempt at a solution

    This is a linear second order ODE where y(t) and that's what I'm solving for. Can this be solved via an integrating factor or does the cot(3t) part make that invalid? Any help is appreciated.
     
  2. jcsd
  3. Apr 26, 2010 #2
    You can solve the complementary homogeneous equation and then the nonhomogeneous equation.

    [itex]y''+9y'=0\Rightarrow m^2+9m=0\Rightarrow m(m+9)=0[/itex] [itex]m=0,-9[/itex]

    [tex]y_c=C_1+C_2e^{-9t}[/tex]

    Now to form the [itex]y_p[/itex] equation, you need to identify what annihilates cos(3t). Do you know what does?
     
  4. Apr 26, 2010 #3

    LCKurtz

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member

    Good luck on that, that's a cotangent, not a cosine. I would suggest variation of parameters.
     
  5. Apr 26, 2010 #4
    I don't really know how to solve this equation. My first (and only) attempt at the solution is an integrating factor and that doesn't work. I'm not well versed in differential equations because I haven't gotten there yet in the math sequence.
     
  6. Apr 26, 2010 #5

    LCKurtz

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member

    You are probably getting a bit ahead of yourself. Integrating factors are used in the first order equations. Your equation is second order and is solved by methods in the "Constant Coefficient" section of your text. There you will learn about solutions to the homogeneous equation and how to find particular solutions to the non-homogeneous equation.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Quick ODE question
  1. Quick help with ODE (Replies: 9)

  2. ODE Question (Replies: 1)

  3. Question on ODEs (Replies: 0)

  4. ODE question (Replies: 9)

Loading...