- #1
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I found a second derivative to the parametric equation :
x = t - e^t
y = t +e^-t
d^2y / dx^2 = e^-t+e^t-2 / (1-e^t)^3
I tried to do some tricks to it, but could not figure out its concavity, any help?
x = t - e^t
y = t +e^-t
d^2y / dx^2 = e^-t+e^t-2 / (1-e^t)^3
I tried to do some tricks to it, but could not figure out its concavity, any help?