#### motornoob101

For the factorial (2n+1)!, I thought the previous term is going to be (2(n-1)+1), which is equal to (2n-1).

Thus (2n+1)!= (2n+1)(2n-1)!

However, in the textbook, they have it as .

$$a_n= \frac{(2n-1)!}{(2n+1)!}=\frac{(2n-1)!}{(2n+1)(2n)(2n-1)!}$$

Are they wrong or I am wrong? Thanks!

#### Diffy

The previous term of (2n+1) is (2n + 1) - 1 not (2(n-1) + 1).

In General if you have (f(x))! You can rewrite as f(x)*(f(x) - 1)!

What you tried which is incorrect is f(x)(f(x-1))!

See the difference?

#### motornoob101

Ah ok. I see thanks. The reason I thought I was correct because I was looking at this example..

Which they are trying to determine if a series is convergent/divergent by the ratio test  Notice how they change 2n-1 to 2(n+1)-1? That's what confused me. Now I know they do it because it is the ratio test and you are trying to put $$a_{n+1}$$ but isn't that the same as what the factorial is doing? Thanks.

#### Attachments

• 795 bytes Views: 220

#### Diffy

You are confusing terms in the sum, and terms within the factorial.

### Physics Forums Values

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving