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Quick question about factorial

  1. Apr 10, 2008 #1
    For the factorial (2n+1)!, I thought the previous term is going to be (2(n-1)+1), which is equal to (2n-1).

    Thus (2n+1)!= (2n+1)(2n-1)!

    However, in the textbook, they have it as .

    [tex] a_n= \frac{(2n-1)!}{(2n+1)!}=\frac{(2n-1)!}{(2n+1)(2n)(2n-1)!}[/tex]

    Are they wrong or I am wrong? Thanks!
  2. jcsd
  3. Apr 10, 2008 #2
    The previous term of (2n+1) is (2n + 1) - 1 not (2(n-1) + 1).

    In General if you have (f(x))! You can rewrite as f(x)*(f(x) - 1)!

    What you tried which is incorrect is f(x)(f(x-1))!

    See the difference?
  4. Apr 10, 2008 #3
    Ah ok. I see thanks. The reason I thought I was correct because I was looking at this example..

    Which they are trying to determine if a series is convergent/divergent by the ratio test


    Notice how they change 2n-1 to 2(n+1)-1? That's what confused me. Now I know they do it because it is the ratio test and you are trying to put [tex]a_{n+1}[/tex] but isn't that the same as what the factorial is doing? Thanks.

    Attached Files:

  5. Apr 10, 2008 #4
    You are confusing terms in the sum, and terms within the factorial.
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